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fo"k; lwph · NEET-2019 SOLVED PAPER · NEET-2018 SOLVED PAPER · NEET-2017 SOLVED PAPER

2019- 1 -2019- 12 2018- 1 -2018- 12 2017- 1 -2017- 12

i`"B la[;k 1.

HkkSfrd txr] ek=kd rFkk

1-6

16.

fLFkj fo|qr foHko

147-156

rFkk /kfjrk

ekiu 7-16

17.

fo|qr&/kjk

157-180

lery esa xfr

17-28

18.

xfreku vkos'k rFkk

181-196

4.

xfr ds fu;e

29-40

5.

dk;Z] ÅtkZ rFkk 'kfDr

41-54

19.

pqEcdRo rFkk inkFkZ

197-202

6.

d.kksa ds fudk; rFkk

55-74

20.

fo|qr&pqEcdh; izsj.k

203-208

21.

izR;korhZ /kjk

209-216 217-220

2.

ljy js[kk esa xfr

3.

?kw.kZu xfr

pqEcdRo

7.

xq#Rokd"kZ.k

75-86

22.

fo|qr&pqEcdh; rjaxsa

8.

Bkslksa ds ;kaf=kd xq.k

87-88

23.

fdj.k izdkf'kdh rFkk

9.

æoksa ds ;kaf=kd xq.k

89-90

10.

inkFkZ dk rkih; xq.k

91-98

11.

Å"ekxfrdh

99-108

12.

v.kqxfr fl¼kar

109-112

13.

nksyu

113-124

14.

rjaxsa

15.

fo|qr vkos'k rFkk {ks=k

izdk'kh; midj.k

221-236

24.

rjax izdkf'kdh

237-242

25.

fofdj.k rFkk inkFkZ dh }Sr izÑfr

243-254

26.

ijek.kq

255-262

125-138

27.

ukfHkd

263-276

139-146

28.

v¼Zpkyd bysDVªksfudh % inkFkZ] ;qfDr;k¡ rFkk ljy ifjiFk 277-295

izpyu fo'ys"k.k AIPMT/NEET (2009-2019) HkkSfrdh

15 16 17 18 19 20 21 22 23 24 25 26 27 28

2019

14

2018

13

2017

11 12

2016 Ph-2

9 10

2016 Ph-1

7 8

2015

6

2014

5

2013

4

2012

3

2011

2

2010

1

vè;k; uke

iz'uksa dh la[;k 2009

vla-

ek=kd rFkk ekiu ljy js[kk esa xfr lery esa xfr xfr ds fu;e dk;Z] ÅtkZ rFkk 'kfDr d.kksa ds fudk; rFkk ?kw.kZu xfr

1

1

1

1

2

1

1

0

1

1

1

2 (Q. 17, 38)

2

3

2

2

2

0

1

1

1

1

1

1 (Q. 15)

2

2

2

2

2

1

1

1

0

1

1

2 (Q. 36, 45)

1

1

2

0

2

3

2

2

2

2

2

2 (Q. 14, 20)

4

2

3

2

2

1

3

1

4

1

2

2 (Q. 30, 33)

3

2

2

3

2

2

3

4

3

3

3

xq#Rokd"kZ.k Bkslksa ds ;kaf=kd xq.k æoksa ds ;kaf=kd xq.k inkFkZ dk rkih; xq.k v.kqxfr fl¼kar Å"ekxfrdh nksyu

1

2

3

3

2

3

2

2

2

2

2

3 (Q. 13, 21, 34) 2 (Q. 26, 31)

0

0

0

0

1

1

1

0

0

1

1

1 (Q. 24)

rjaxsa fo|qr vkos'k rFkk {ks=k fLFkj fo|qr foHko rFkk /kfjrk fo|qr&/kjk xfreku vkos'k rFkk pqEcdRo pqEcdRo rFkk inkFkZ fo|qr&pqEcdh; izsj.k izR;korhZ /kjk fo|qr&pqEcdh; rjaxsa fdj.k izdkf'kdh rFkk izdk'kh; midj.k rjax izdkf'kdh fofdj.k rFkk inkFkZ dh }Sr izÑfr ijek.kq ukfHkd v¼Zpkyd bysDVªksfudh % inkFkZ] ;qfDr;k¡ rFkk ljy ifjiFk

0

0

0

0

1

1

1

1

2

1

1

2 (Q. 35, 40)

2

2

0

2

2

2

2

3

2

2

1

1 (Q. 22)

1

0

0

0

1

1

2

1

2

1

1

–

2

1

2

0

2

2

2

3

1

2

3

2 (Q. 6, 10)

2

2

2

0

0

1

2

0

1

2

1

2

2

1

1

2

–

1

3

2

2

2

3 (Q. 11, 12, 18) –

1

2

1

2

1

3

1

1

1

1

2

3 (Q. 2, 28,43)

1

1

2

1

1

3

1

1

1

2

–

–

5

4

3

4

2

4

3

2

2

2

3

3 (Q. 5, 8, 39)

1

0

2

2

2

2

2

3

3

2

2

2 (Q. 7, 23)

2

2

1

1

1

1

0

1

1

1

1

1 (Q. 3)

2

5

1

2

1

1

1

0

0

1

1

2 (Q. 16, 44)

1

1

2

1

2

1

1

2

2

1

1

–

–

–

1

–

1

1

1

1

1

1

1

2 (Q. 9, 37)

0

2

2

5

2

1

2

3

4

2

2

3 (Q. 27, 32, 42)

2

1

–

1

2

2

2

2

1

3

3

1 (Q. 4)

3

3

8

3

2

2

2

2

2

2

2

1 (Q. 19)

2

2

1

3

1

2

2

1

1

1

1

1 (Q. 41)

3

2

2

4

2

1

1

1

–

1

1

1 (Q. 29)

4

5

4

5

2

2

2

3

3

3

3

2 (Q. 1, 25)

50 50 50 50 45 45 45 45 45 45 45 45 dqy iz'u lauksV% dks"Bd esa fn;s x;s la[;k NEET 2019 esa iwNs x;s iz'uksa ds Øe la[;k] tks i`"B la- 2019&1&2019&5 ij fn;k x;k gS] dks n'kkZrk gSA

NEET Solved Paper 2019 1. 0

+6V R

A 1 0

LED (Y) R

B 1

2.

vkjs[k ds ifjiFk }kjk fu:fir lgh cwyh; izpkyu gS% (1) AND (2) OR (3) NAND (4) NOR f=kT;k R ds fdlh

4.

[kks[kys /krq ds xksys dks ,dleku vkosf'kr fd;k x;k gSA dsUnz ls nwjh r ij xksys ds dkj.k fo|qr {ks=k% (1) tc r c R ds fy, c R ds fy, cqdko ij gksA 21. rA vkSj rB f=kT;kvksa ds ladsUnzh o`Ùkksa ij nks d.k A vkSj B Øe'k% uA vkSj uB osxksa ls ,dleku o`Ùkh; xfr dj jgs gSaA buds ?kw.kZu dk vkorZdky leku gSA A vkSj B dh dks.kh; pkyksa dk vuqikr gksxk% 20.



(1) Mgl (2) MgL (3)

1 1 Mgl (4) MgL 2 2

fdlh p- izdkj ds v/Zpkyd ds fy, fuEufyf[kr esa ls dkSu&lk dFku lgh gSA (1) bysDVªkWu cgqla[;d okgd gSa rFkk f=kdla;kstd ijek.kq eknd (MksiSUV) gSaA (2) fooj cgqla[;d okgd gSa rFkk f=kdla;kstd ijek.kq eknd (MksiSUV) gSaA (3) fooj cgqla[;d okgd gSa rFkk iapla;kstd ijek.kq eknd (MksiSUV) gSaA (4) bysDVªkWu cgqla[;d okgd gSa rFkk iapla;kstd ijek.kq eknd (MksiSUV) gSaA 25.

PHYSICS

2019-4

26.

fdlh nzO;eku m dks i`Foh ds i`"B ls Å¡pkbZ h, tks i`Foh dh f=kT;k ds cjkcj gS] rd Åij mBkus esa fd;k x;k dk;Z gS%



(1) mgR (2) 2 mgR 1 3 (3) mgR (4) mgR 2 2 27. iw.kZ vkarfjd ijkorZu esa tc laidZ ds ekè;eksa

ds ;qxy ds fy, vkiru dks.k Økafrd dks.k ds cjkcj gksrk gS] rks viorZu dks.k fdruk gksxk\



(1) 180°



(2) 0°

(3) vkiru

dks.k ds cjkcj



(4) 90°

28.

nks fcUnq vkos'k A vkSj B ftu ij Øe'k% +Q vkSj –Q vkos'k gSa] ,d nwljs ls dqN nwjh ij fLFkr gSa vkSj buds chp yxus okyk cy F gSA ;fn A dk 25% vkos'k B dks LFkkukUrfjr dj fn;k tk,] rks vkos'kksa ds chp cy gks tk,xk%

9F 16 16F 4F (3) (4) 9 3 29. a-d.k esa gksrs gSa%

(1) F

(2)

vkSj 2 U;wVªkWu (2) 2 bysDVªkWu] 2 izksVkWu vkSj 2 U;wVªkWu (3) dsoy 2 bysDVªkWu vkSj 4 izksVkWu (4) dsoy 2 izksVkWu 30. pky m xfreku 4m nzO;eku dk dksbZ fi.M A fojke esa fLFkr 2m nzO;eku ds fdlh fi.M B ls vkeus&lkeus lh/s izR;kLFk izÑfr dk la?kV~V djrk gSA la?kV~V ds i'pkr la?kV~V djus okys fi.M A dh {kf;r ÅtkZ dk Hkkx gS%

32. bUnz/uq"k ds lanHkZ esa (1) tc fdlh ty

xyr mÙkj pqfu,A dh cwan eas izdk'k dh fdj.ksa nks ckj vkarfjd ijkorZu djrh gSa] rks dksbZ f}rh;d bUnz/uq"k curk gSA (2) f}rh;d bUnz/uq"k esa o.kksZa dk Øe mRØfer gks tkrk gSA (3) dksbZ izs{kd bUnz/uq"k rc ns[k ldrk gS tc lw;Z mlds lkeus gksrk gSA (4) bUnz/uq"k lw;Z ds izdk'k ds fo{ksi.k] viorZu vkSj ijkorZu dk la;qDr izHkko gSA 33. fdlh d.k ij y- fn'kk esa dksbZ cy F = 20 + 10y dk;Z dj jgk gS] ;gk¡ F U;wVu esa rFkk y ehVj esa gSaA bl d.k dks y = 0 ls y = 1 m rd xfr djkus esa fd;k x;k dk;Z gS% (1) 30 J (2) 5 J 34. nzO;eku 100 kg vkSj



i`Foh ds dsUnz dh vksj vk/h nwjh ij bldk Hkkj fdruk gksxk\



(1) 150 N

(2) 200 N



(3) 250 N

(4) 100 N

(1) 3 J

(2) 30 kJ (3) 2 J (4) 1J

35. 2 m Å¡pkbZ

ds iw.kZ :i ls ty ls Hkjs fdlh [kqys VSad esa ryh ds fudV 2 mm2 vuqizLFk dkV {ks=kiQy dk dksbZ NksVk fNnz mifLFkr gSA g = 10 m/s2 ysrs gq, [kqys fNnz ls izokfgr ty dh nj gksxh yxHkx%

(1) dsoy 2 izksVkWu

1 8 (1) (2) 9 9 4 5 (3) (4) 9 9 31. fdlh fi.M dk i`Foh ds i`"B ij Hkkj 200 N gSA

(3) 25 J (4) 20 J

f=kT;k 2 m dh dksbZ pdrh fdlh {kSfrt iQ'kZ ij yq lgjk > luhyk > lcSaxuh

yky jax dk rjaxnSè;Z vf/dre gksrk gSA F nRT 2 As U ∝ T

10. (2) U=

rkieku esa o`f¼ ls xSl ds xfrt ÅtkZ esa o`f¼ gksxhA 11. (4) t = 0 ij] y = 3 tks fd vf/dre foLFkkiu gS] vr% leh- cosine iQyu gksxkA



R eq =

R 3R +R= 2 2

y

2

2E …(ii) 3R



'kfDr (Pf) =



lehdj.k (i) esa (ii) ls Hkkx nsus ij]

Pt=0 T=4s x

Pi 3E 2 3R = = 9:4 Pf 2R 2E 2

izØe esa] okrkoj.k ls Å"ek dk vknku&iznku ugha gksrk gSA 7. (3) vkUrfjd (d < R) pkyd ds vUnj pqEcdh; {ks=k B = Kd ..... (i) ;g ,d lery js[kk gS tks 'O' ls xqtjrk lrg ij] (d = R)

10 V1 =i1 × 10 = × 10 =10 okYsV 10 f}rh;

ifjiFk ds fy;s

10 V2 = i 2 × 10 = × 10 =10 okYsV 10

12. (4) dks.k

dk foLFkkiu ,d iw.kZ nksyu esa 'kwU; gS] vr% vkSlr osx ,d iw.kZ nksyu esa gksxkA

gSA

µ 1 B= 0 2π d d vf/dre lrg ds ckgj (d > R) µ 1 B B= 0 2π d 1 O R d ;k B ∝ ∴ vfrijoyfid d 8. (3) vkn'kZ oksYVehVj ds fy;s izfrjks/] = ∞ vkn'kZ vehVj ds fy;s] izfrjks/ = 0

ifjiFk ds fy;s]

2π 2π π ω = = = rad/s ( ∵ T = 4 s) T 4 2 π y a cos ωt ⇒= y 3cos t = 2



6. (2) :¼ks"e

izFke

\

=

y f − yi foLFkkiu 0 = = T le;kUrjky

13. (1) dk;Z&ÅtkZ izes; 1 W I ωf2 − ωi2 = 2

(





)

ls

fn;k gS]

q = 2p ifjØe.k/feuV q = 2p × 2p = 4p2 rad 2π ωi = 3 × rad / s 60 wf = 0 rad/s wf ,oa wi dk eku j[kus ij] ⇒ – τθ=

⇒ –τ=

(

1 1 2 2 × mr 0 – ωi2 2 2

)

(

)

1 1 2π   × × 2 × 4 × 10 –2  –3 ×   2 2 60 

⇒ t = 2 × 10–6 N-m

4π 2

2

PHYSICS

2019-8

14. (3) xqVds

dk nzO;eku m = 10 kg; osyukdkj Mªe dh f=kT;k] r = 1m; xqVds ,oa osyu ds vkUrfjd fnoky ds chp ?k"kZ.k xq.kkad µ = 0.1; xqVds ds larqyu ds fy;s] lhekUr ?k"kZ.k] f L ≥ mg ⇒ µN ≥ mg

⇒ µ rω2 ≥ mg

;gk¡, N = mrw2

N

g rµ

;k, m ≥

fL mrω2

15. (1) rSjkd Hkwry

= NBA cos 90° – BA cos 0° = – NBA = – 800 × 5 × 10–5 × 0.05



= –2 × 10–2 oscj

∆φ −( −)2 × 10 −3 Wb θ= − = = 0.02 V ∆t 0.1 s [uksV : ;g vkSlr izsfjr emf gSA] 17. (2) fn;k

gS] x =

mg

% =kqfV

g ;k, ω min = rµ

A 2 B1 2 C1 3D3

∆x ∆A 1 ∆B × 100= 2 × 100 + × x A 2 B

1 ∆C ∆D × 100 + 3 × 100 3 C D 1 1 = 2 × 1% + × 2% + × 3% + 3 × 4% 2 3 = 2% + 1% + 1% + 12% = 16% 100 +

10 = 10 rad/s 0.1 × 1

∴= ω min



dk unh ds lkis{k] osx VSR = 20 m/s ds lkis{k unh dk osx] VRG = 10 m/s

18. (2) B

N

A 2 + B2

VRG W

VSR

θ

VSG

E

S    SG VSR + V RG V=  V RG 10 = ⇒= sin θ  sin θ 20 VSR 1 ⇒ sin θ= ∴ θ= 30° west 2

unh

dks lcls NksVs jkLrs ls ikj djus ds fy;s] rSjkd dks LVªksd 30° if'pe yxkuk gksxkA 16. (4) fn;k gS pqEcdh; {ks=k B = 5 × 10–5 T dq.Myh esa iQsjksa dh la[;k N = 800 dq.Myh dk {ks=kiQy A = 0.05 m2 ?kw.kZu esa yxk le;] = Dt = 0.1 s izkjafHkd dks.k q1 = 0° vfUre dks.k q2 = 90° pqEcdh; iQyd~l esa ifjorZu Df

fn;k

y = A0 + A sin wt + B sin wt

vc

A

x;k leh-

eku ysrs gSa] (y – A0) = g

y – A0 = Asin wt + B sin wt

g = A sin wt + B cos wt =

A 2 + B2 sin (wt + f)

;g S.H.M. gSA ;gk¡ cos f = rFkk sin f = vr% =

A 2

A + B2 B 2

A + B2

ifj.kkeh vk;ke] A 2 + B2

NEET Solved Paper 2019 19. (2) bysDVªkWu



= λ

2019-9

dk Ms&czksXyh rjaxnSè;Z]

12.27 12.27 × 10 –10 = Å = 12.27 × 10 –12 m V 10000

mv 2 mv 2 [vfHkdsUnzh; cy = ] r r 2 mv ⇒ T = mg + r 20. (3) T − mg =

p rα = α 2eB p rH = eB p rα 2eB ⇒

T v mg

pw¡fd U;wure foUnq ij] osx dk eku vf/dre gS] vr% nzO;eku ds U;wure fLFkfr esa ruko vf/dre gksxk ftlls VwVus dh laHkkouk vf/dre gksxkA

21. (4) ekuk

fd TA rFkk TB Øe'k% d.k A rFkk B dk vkorZdky gSaA iz'ukuqlkj]

TA = TB = T ;fn wA rFkk wB muds



[fn;k

rB rA

dks.kh; pky gSa] vr%

2π 2π = ωA rFkk= ωB TA TB ω T T ∴ A =B == 1:1 ω B TA T 22. (4) l’Cu = lCu (1 + aCu DT) DlCu = lCu aCu DT l’Al = lAl (1 + aAl DT) DlAl = lAl aAl DT pw¡fd yEckbZ esa ifjorZu rkieku ls Lora=k gS \ aCulCu = aAllAl ⇒ 1.7 × 10–5 × 88 cm = 2.2 × 10–5 × lAl 1.7 × 88 = ⇒ lAl = 68 cm 2.2

P

gS] pH = pa = p]

rH 2 = rα 1

24. (3) ;gk¡ Kx 0 = Mg

r



mv

dh f=kT;k = r= qB = qB pH H+ vk;u ds fy;s] rH = eB a d.k ds fy;s] 23. (1) iFk

;gk¡ K = cy fu;rkad 1 DE = Kx 02 2 1 Mg = × x 02 2 x 0

L



1 = Mgx 0 Mg 2 c