9789391224325 Flipbook PDF


73 downloads 114 Views 11MB Size

Recommend Stories


Porque. PDF Created with deskpdf PDF Writer - Trial ::
Porque tu hogar empieza desde adentro. www.avilainteriores.com PDF Created with deskPDF PDF Writer - Trial :: http://www.docudesk.com Avila Interi

EMPRESAS HEADHUNTERS CHILE PDF
Get Instant Access to eBook Empresas Headhunters Chile PDF at Our Huge Library EMPRESAS HEADHUNTERS CHILE PDF ==> Download: EMPRESAS HEADHUNTERS CHIL

Story Transcript

2/25, Ansari Road Daryaganj, New Delhi-110002

COPYRIGHT © JBC PRESS ALL RIGHTS RESERVED ALL RIGHTS RESERVED. NO PART OF THIS PUBLICATION MAY BE REPRODUCED, STORED IN A RETRIEVAL SYSTEM, OR TRANSMITTED, IN ANY FORM OR BY ANY MEANS, ELECTRONIC, MECHANICAL, PHOTOCOPYING, RECORDING OR OTHERWISE, WITHOUT THE PRIOR PERMISSION OF THE COPYRIGHT OWNERS.

DISCLAIMER

ERRORS, IF ANY, ARE PURELY UNINTENTIONAL AND READERS ARE REQUESTED TO COMMUNICATE SUCH ERRORS TO THE PUBLISHER TO AVOID DISCREPANCIES IN FUTURE. PRINTED & BOUND IN INDIA PUBLISHED BY:

JBC PRESS

2/25, ANSARI ROAD, DARYA GANJ, NEW DELHI-110 002 PH.: 011-41564440, MOB. 09910115201 E-MAIL: [email protected] • WEB: WWW.JBCPRESS.COM

T

Preface Preface

he purpose of this edition of "JEE ADVANCED" MODEL SOLVED PAPERS (‘Wake Up’) is to introduce the pattern of questions which in based on frequently asked in 44 years of “JEE ADVANCED EXAMS” with detailed explanations. We still cleave to show the scheme of exam which prolonged with recent JEE ADVANCED EXAMS that students eagerly required to know and want to have model practice papers ‘book’ to crack the most prestigious competitive exam. "JEE ADVANCED MODEL PAPERS" book hews to be framed on certain important sections on which certain mood of questions are frequently asked (only 60% topics are important). Only objective of this book is, students could easily practice over each model paper which make them assured for obtaining good marks incoming exam. We muster up the energy in direction for making strategy of model solving papers – 10 Full length test (Paper-1 and Paper-2=Total 20 Papers). JEE ADVANCED MODEL PAPERS based on the latest pattern with comprehensive solutions for each model test paper to create demand in required gap market. The insist way to make optimum use of this book is to go through the questions, attempt solutions, and then cross check your solutions with the solutions provided in the book. In fact, this act of self-assessment, if you can do honestly to yourself, so must put you on the track framed as per ‘Required Path’. This indeed, if got can help you in achieving things far beyond than the stated target.

We will sincerely and gratefully welcome the suggestions which the reader may deem necessary to make for the improvement of this book.

Editor-in-chief

Amitabh Ranjan

Contents JEE ADVANCED 1-Model Paper (Paper-I and Paper-II)

1-45

JEE ADVANCED 2-Model Paper (Paper-I and Paper-II)

46-83

JEE ADVANCED 3-Model Paper (Paper-I and Paper-II)

84-131

JEE ADVANCED 4-Model Paper (Paper-I and Paper-II)

132-178

JEE ADVANCED 5-Model Paper (Paper-I and Paper-II)

179-210

JEE ADVANCED 6-Model Paper (Paper-I and Paper-II)

211-244

JEE ADVANCED 7-Model Paper (Paper-I and Paper-II)

245-278

JEE ADVANCED 8-Model Paper (Paper-I and Paper-II)

279-310

JEE ADVANCED 9-Model Paper (Paper-I and Paper-II)

311-354

JEE ADVANCED 10-Model Paper (Paper-I and Paper-II)

355-389

Practice Set

JEE ADVANCED

1

Model Paper

PAPER-I

Physics Section-I



1 T  .   LD   





h

d

2r

 

Steel rivets



Steel Copper



r   h    3

hrlg 2cos  r  r  h   g  3 2

d/2



1 3







Cu  Cu T YCu

2

JEE ADVANCED

r 2 g 2m

1 2



r 2 g m

Sphere B d

 O

R

Sphere A

2   3

 m B

A m K

t1 10



2 mg x

P1

2 mg x

k m

M

2

M1

P2 37º

Section-II T g

M3

3

MODEL PAPER-1

O

2 3v2 gL

Section-III

A

L/8



L 2U0

B

u

U

U0

D

C

A

B

p0

p

4p0 2p0 p0

p

2p0 p0

60 cm K1 A

m C

p

K2

v D

B

2p0 p0

D

B

A V

V0

D C

A

V0/2

4p0

2p0

C

V0/2

4p0



B V

V0

C B

D

V0/2

A V

V0

4

JEE ADVANCED

p

D

4p0

C

2p0 p0

V

D

2T0 A p0

2p0 p

p0

2p0 p

T

2T0

Red Violet

Angular dispersion   V –  R     –1  Mean deviation





C

D

A p0



C



B 2p0 p

D

A p0 p



4p0

4p0











C

T

T0

V

B

2T0

T0

4p0

R

White



T

A

A

B

D

2T0

V0

C

T

T0



B V0/2

T0



A



A1

B 2p0

it e Wh m a be

   

1



 

ite Wh m a e b

2

A2

  



 

MODEL PAPER-1

5

Chemistry Section-I

O

(i) C2H5MgBr

(ii) NH4Cl, H2O

O

(i) CH3MgBr

(ii) NH4Cl, H2O

O

(i) CH3MgBr

OCH3

 PCl 4 

O

 PCl6– 

CH3

(ii) NH4Cl, H2O

+ 2C2H5MgBr

NH2

1 XA

(i) THF,  (ii) H3O+

1 YA

1 XA 1 YA

pA – pB pB

A(C8H14)

Optically active

O3

(CH 3)2S

B(C8H14O2)

( pB – p A) pB

Dil. NaOH

(C)

O

( p A – p B) pB ( p B – p  A ) p B

Section-II

O3 , NO 2 , NO+2 , N 2O,SO2 , N3– ,CS2 ,C3O2 ,H2S

6

JEE ADVANCED

(CN)2–

2 dhkl

a2

h  k2  l2 2

Y k

Cu(H2O)26  H2O  Cu(H2O)5 (OH)



l

 H3O+ , K 10 –5 and 3 1.5 1.14)

h

X

Z

value of sin Section-III K

1  P  Q

K2

3 8 CH3 (a)

O

, O

CH3

y x

(b)

O

,

CH3

(c)

O

O

O , O

(d)

O

,

H

MODEL PAPER-1

7

Mathematics Section-I

– +

OK 

abc

bca cab  z3   z  1

Cl C

(i) Sn/HCl (ii) CH3/COCl

(iii) CH 3 CH (ii) H3O+/

CH/H+

O

N

A

(i) Br2/Fe

B

(ii) KCN, 

0



O







 NH2 Cl

NH2

COCH3

COCH3

NH2





 (0,  ) 

Cl







1  sin t

x



NH2

2

3 3 3 z1 4

(i) KCN,  (ii) Br2/Fe

 z3 – z1   z – z  2 1

1  y  bx  x  1  ( y– bx ) 2 x







  

    2



   2



 

8

JEE ADVANCED

 







b  (a  b) b

    a  (a  b)    2   a 

5



1 3



yx2

5

Section-II



 ck



 2





3

x3  1

Section-III 



11(k – 9)   n 9 n –1 58   is n lim –  n     n /11  ( n – k ) ( n  k )  k  10 log 2.e  k0   (–1) n –1 x 2 n    (–1)n –1 x 4 n  1 sin –1    + cos    n –1 n –1  n 1 3   n 1 3 

z3  1 z2 x  11

x2 z

 1    5

(log10 x)2  (log10 y)2  (log10 z)2 {ai  b j

y3  1 y2 z y2 x

equation yz2 



17 and other two vertices are on parabola y =

1 2      2 { a b – (a . b) a} a

 –1    5







 a. b   2  a – b a

2

5









3 7 a x , a y  2 4













2 p (2 – p) (1 – p)

p2 (2 – p) (1 – p)

p (2 – p) (1 – p)

f (b) – f (a) b– a

2 p (2 – p) (1 – p)







9

MODEL PAPER-1



If 





f (b) – f (a) f (c)  g(b) – g (a) g (c)













sin a – sin  cos  – cos 

 2

   









PAPER-II Physics Section-I

4 2

3 2

g 7 g 3

P

O 

p, V , T 2 p,2V , T I II

V

4 r – v2 t 2 2

V

3V 5

12V 5

2r – v2 t 2

5p 3

v 2r

V

Get in touch

Social

© Copyright 2013 - 2024 MYDOKUMENT.COM - All rights reserved.