ELECTROTÉCNIA

KIRCHOFF =208·230−[−140·(140)]= 28240 I1=[(0·230)−(−140·10)]/28240= 49 mA I2=[(280·10)−(−140·0)]/28240= 73 mA I2=Ir3 Vr3= Ir3·R3 73·68= 4'9V THEVENIN Vth= (E1−E2)·[R2/(R1+R2)]+E2 (10−10)·[140/(140+68)]+10= 10V Rth= R1·R2/R1+R2 140·68/140+68= 45'79 Rth'=R3·R4/R3+R4 68·22/68+22= 16'62 I1= Vth/(Rth− Rth') 10/(45'79−16'62)= 34 mA I2= Vth/(Rth+R3+R4) 10/(45'79+68+22)= 79 mA I2=Ir3 Vr3= Ir3·R3 73·68= 4'9V

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